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610x-6000-x^2=0
We add all the numbers together, and all the variables
-1x^2+610x-6000=0
a = -1; b = 610; c = -6000;
Δ = b2-4ac
Δ = 6102-4·(-1)·(-6000)
Δ = 348100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{348100}=590$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(610)-590}{2*-1}=\frac{-1200}{-2} =+600 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(610)+590}{2*-1}=\frac{-20}{-2} =+10 $
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